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-10^2-3a^2=-310
We move all terms to the left:
-10^2-3a^2-(-310)=0
We add all the numbers together, and all the variables
-3a^2+210=0
a = -3; b = 0; c = +210;
Δ = b2-4ac
Δ = 02-4·(-3)·210
Δ = 2520
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2520}=\sqrt{36*70}=\sqrt{36}*\sqrt{70}=6\sqrt{70}$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6\sqrt{70}}{2*-3}=\frac{0-6\sqrt{70}}{-6} =-\frac{6\sqrt{70}}{-6} =-\frac{\sqrt{70}}{-1} $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6\sqrt{70}}{2*-3}=\frac{0+6\sqrt{70}}{-6} =\frac{6\sqrt{70}}{-6} =\frac{\sqrt{70}}{-1} $
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